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Probability · Lecture 43 of 76 · 5:37

The Sum of Discrete and Continuous Random Variables

The Sum of Discrete and Continuous Random Variables on YouTube

Study guide

What this lecture covers

This is a short worked problem from MIT 6.041SC's derived distributions unit. It answers a specific question left open by the main convolution lecture: what if you add a discrete random variable X and a continuous random variable Y, rather than two variables of the same type? The problem walks through the standard CDF-then-derivative method, conditioning on the discrete variable to make the calculation tractable.

After watching, you should be able to derive the density of a sum of a discrete and a continuous independent random variable, and recognize how the result relates to the convolution formula covered in the main lecture.

Key ideas

  • Standard approach: find the CDF of Z = X + Y first, then differentiate to get the density.
  • Condition on the discrete variable: applying the total probability theorem by conditioning on X (rather than the continuous Y) avoids the technical difficulties of conditioning on a continuous variable.
  • Independence lets you drop the conditioning: once X is fixed, independence of X and Y means the conditional CDF of Y given X equals the plain CDF of Y.
  • Differentiating a sum: after summing the conditional CDF terms over all values of x, term-by-term differentiation (justified formally for a finite, and informally for a countable, number of terms) yields the density of Z.
  • Result resembles convolution: the final formula, f_Z(z) = sum over x of f_Y(z - x) * P_X(x), mirrors the convolution formula, with a PMF replacing one of the two densities that would appear in the fully continuous case.

Before you watch

  • Know the CDF-then-derivative method for finding a density, and the convolution formula for sums of two independent continuous or two independent discrete random variables.
  • Be comfortable applying the total probability theorem by conditioning on a random variable.

Check your understanding

  1. Why does the problem condition on the discrete variable X rather than the continuous variable Y?
  2. Why is it valid to drop the conditioning on X when writing the CDF of Y given X = x?
  3. What role does independence of X and Y play in this derivation?
  4. How does the resulting formula compare to the convolution formula for two continuous random variables?

Vocabulary

tractable (adjective)
Easy enough to handle or solve with the tools you have.
Conditioning on the discrete variable makes the problem tractable.
condition on (phrase)
To assume a certain variable's value is known and calculate from there.
We condition on the discrete variable X first.
total probability theorem (phrase)
A rule for finding an overall probability by adding contributions from each possible case.
The total probability theorem breaks the CDF into pieces over each value of X.
term-by-term (phrase)
Handling each part of a sum one at a time, separately.
We differentiate the sum term-by-term to get the density.
countable (adjective)
Able to be listed one by one, even if there are infinitely many.
X takes a countable number of possible values.
resemble (verb)
To look similar to something else.
The final formula resembles the convolution formula.
convolution (noun)
A formula for combining two distributions to find the distribution of their sum.
The result mirrors the convolution formula from the main lecture.
differentiate (verb)
To take the derivative of a function.
We differentiate the CDF to get the density.
derivative (noun)
A measure of how fast a function changes at a point.
Taking the derivative of the CDF gives the density function.
sum (noun)
The result of adding two or more quantities together.
Z is defined as the sum of a discrete and a continuous variable.
formula (noun)
A fixed rule expressed with symbols for calculating something.
The final formula gives the density of Z directly.
technical difficulty (phrase)
A tricky or awkward detail that complicates a calculation.
Conditioning on a discrete variable avoids the technical difficulties of conditioning on a continuous one.
finite (adjective)
Having a limited, countable number of parts, not endless.
Term-by-term differentiation is formally justified for a finite number of terms.
informally (adverb)
In a loose way, without a fully strict proof.
The result is justified informally for a countable number of terms.
formally (adverb)
In a strict, rigorous, mathematically proven way.
The step is formally justified only for a finite sum.
mirror (verb)
To closely match or reflect the structure of something else.
The new formula mirrors the standard convolution formula.
fix (verb)
To hold a variable's value constant for the rest of a calculation.
Once X is fixed, independence simplifies the conditional CDF.
plain (adjective)
Simple and ordinary, without extra conditions.
The conditional CDF of Y given X equals the plain CDF of Y.
specific (adjective)
Particular and clearly defined, not general.
This problem answers a specific question left open by the main lecture.
standard (adjective)
Usual and widely accepted as the normal way of doing something.
The CDF-then-derivative method is the standard approach here.
worked problem (phrase)
An example problem solved step by step to show the method.
This is a short worked problem from the derived distributions unit.
unit (noun)
A section of a course covering one connected topic.
This problem comes from the course's derived distributions unit.
recognize (verb)
To notice and identify something as familiar.
You should recognize how the result relates to convolution.
apply (verb)
To use a method or rule in a specific situation.
The total probability theorem is applied by conditioning on X.
drop (verb)
To remove something that is no longer needed.
Independence lets you drop the conditioning on X.
independent (adjective)
Not affected by or related to another variable.
X and Y are assumed to be independent random variables.

From the YouTube description

MIT 6.041SC Probabilistic Systems Analysis and Applied Probability, Fall 2013
View the complete course: http://ocw.mit.edu/6-041SCF13
Instructor: Jagdish Ramakrishnan

License: Creative Commons BY-NC-SA
More information at http://ocw.mit.edu/terms
More courses at http://ocw.mit.edu

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