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Probability · Lecture 43 of 76 · 5:37
The Sum of Discrete and Continuous Random Variables
Study guide
What this lecture covers
This is a short worked problem from MIT 6.041SC's derived distributions unit. It answers a specific question left open by the main convolution lecture: what if you add a discrete random variable X and a continuous random variable Y, rather than two variables of the same type? The problem walks through the standard CDF-then-derivative method, conditioning on the discrete variable to make the calculation tractable.
After watching, you should be able to derive the density of a sum of a discrete and a continuous independent random variable, and recognize how the result relates to the convolution formula covered in the main lecture.
Key ideas
- Standard approach: find the CDF of Z = X + Y first, then differentiate to get the density.
- Condition on the discrete variable: applying the total probability theorem by conditioning on X (rather than the continuous Y) avoids the technical difficulties of conditioning on a continuous variable.
- Independence lets you drop the conditioning: once X is fixed, independence of X and Y means the conditional CDF of Y given X equals the plain CDF of Y.
- Differentiating a sum: after summing the conditional CDF terms over all values of x, term-by-term differentiation (justified formally for a finite, and informally for a countable, number of terms) yields the density of Z.
- Result resembles convolution: the final formula,
f_Z(z) = sum over x of f_Y(z - x) * P_X(x), mirrors the convolution formula, with a PMF replacing one of the two densities that would appear in the fully continuous case.
Before you watch
- Know the CDF-then-derivative method for finding a density, and the convolution formula for sums of two independent continuous or two independent discrete random variables.
- Be comfortable applying the total probability theorem by conditioning on a random variable.
Check your understanding
- Why does the problem condition on the discrete variable X rather than the continuous variable Y?
- Why is it valid to drop the conditioning on X when writing the CDF of Y given X = x?
- What role does independence of X and Y play in this derivation?
- How does the resulting formula compare to the convolution formula for two continuous random variables?
Vocabulary
- tractable (adjective)
- Easy enough to handle or solve with the tools you have.
Conditioning on the discrete variable makes the problem tractable. - condition on (phrase)
- To assume a certain variable's value is known and calculate from there.
We condition on the discrete variable X first. - total probability theorem (phrase)
- A rule for finding an overall probability by adding contributions from each possible case.
The total probability theorem breaks the CDF into pieces over each value of X. - term-by-term (phrase)
- Handling each part of a sum one at a time, separately.
We differentiate the sum term-by-term to get the density. - countable (adjective)
- Able to be listed one by one, even if there are infinitely many.
X takes a countable number of possible values. - resemble (verb)
- To look similar to something else.
The final formula resembles the convolution formula. - convolution (noun)
- A formula for combining two distributions to find the distribution of their sum.
The result mirrors the convolution formula from the main lecture. - differentiate (verb)
- To take the derivative of a function.
We differentiate the CDF to get the density. - derivative (noun)
- A measure of how fast a function changes at a point.
Taking the derivative of the CDF gives the density function. - sum (noun)
- The result of adding two or more quantities together.
Z is defined as the sum of a discrete and a continuous variable. - formula (noun)
- A fixed rule expressed with symbols for calculating something.
The final formula gives the density of Z directly. - technical difficulty (phrase)
- A tricky or awkward detail that complicates a calculation.
Conditioning on a discrete variable avoids the technical difficulties of conditioning on a continuous one. - finite (adjective)
- Having a limited, countable number of parts, not endless.
Term-by-term differentiation is formally justified for a finite number of terms. - informally (adverb)
- In a loose way, without a fully strict proof.
The result is justified informally for a countable number of terms. - formally (adverb)
- In a strict, rigorous, mathematically proven way.
The step is formally justified only for a finite sum. - mirror (verb)
- To closely match or reflect the structure of something else.
The new formula mirrors the standard convolution formula. - fix (verb)
- To hold a variable's value constant for the rest of a calculation.
Once X is fixed, independence simplifies the conditional CDF. - plain (adjective)
- Simple and ordinary, without extra conditions.
The conditional CDF of Y given X equals the plain CDF of Y. - specific (adjective)
- Particular and clearly defined, not general.
This problem answers a specific question left open by the main lecture. - standard (adjective)
- Usual and widely accepted as the normal way of doing something.
The CDF-then-derivative method is the standard approach here. - worked problem (phrase)
- An example problem solved step by step to show the method.
This is a short worked problem from the derived distributions unit. - unit (noun)
- A section of a course covering one connected topic.
This problem comes from the course's derived distributions unit. - recognize (verb)
- To notice and identify something as familiar.
You should recognize how the result relates to convolution. - apply (verb)
- To use a method or rule in a specific situation.
The total probability theorem is applied by conditioning on X. - drop (verb)
- To remove something that is no longer needed.
Independence lets you drop the conditioning on X. - independent (adjective)
- Not affected by or related to another variable.
X and Y are assumed to be independent random variables.
From the YouTube description
MIT 6.041SC Probabilistic Systems Analysis and Applied Probability, Fall 2013
View the complete course: http://ocw.mit.edu/6-041SCF13
Instructor: Jagdish Ramakrishnan
License: Creative Commons BY-NC-SA
More information at http://ocw.mit.edu/terms
More courses at http://ocw.mit.edu
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